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@@ -0,0 +1,38 @@
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package top100liked
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import (
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"fmt"
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"testing"
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)
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// https://leetcode.cn/problems/search-insert-position/description/?envType=study-plan-v2&envId=top-100-liked
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func searchInsert(nums []int, target int) int {
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start, end := 0, len(nums)-1
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for start < end {
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mid := start + (end-start)/2
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if nums[mid] == target {
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return mid
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} else if nums[mid] > target {
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end = mid - 1
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} else {
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start = mid + 1
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}
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}
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if nums[end] < target {
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return end + 1
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}
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return end
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}
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func Test(t *testing.T) {
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fmt.Printf("%+v\n", searchInsert([]int{1, 3, 5, 6}, 5))
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}
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func Test2(t *testing.T) {
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fmt.Printf("%+v\n", searchInsert([]int{1, 3, 5, 6}, 2))
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}
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func Test3(t *testing.T) {
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fmt.Printf("%+v\n", searchInsert([]int{1, 3, 5, 6}, 7))
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}
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@@ -0,0 +1,58 @@
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package top100liked
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import (
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"fmt"
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"testing"
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)
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// https://leetcode.cn/problems/search-a-2d-matrix/?envType=study-plan-v2&envId=top-100-liked
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// 难在边界条件
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func searchMatrix(matrix [][]int, target int) bool {
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// 第一列竖着找
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m := len(matrix)
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n := len(matrix[0])
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for i := range m {
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cur := matrix[i][0]
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switch {
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case cur == target:
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return true
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case cur > target:
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// target 可能在 i-1 行
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if i-1 >= 0 {
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for j := range n - 1 {
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if matrix[i-1][j+1] < target {
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continue
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} else if matrix[i-1][j+1] == target {
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return true
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} else if matrix[i-1][j+1] > target {
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return false
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}
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}
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}
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case cur < target:
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// 如果 i == m-1 (最后一行)
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if i == m-1 {
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for j := range n - 1 {
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if matrix[i][j+1] < target {
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continue
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} else if matrix[i][j+1] == target {
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return true
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} else if matrix[i][j+1] > target {
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return false
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}
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}
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}
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continue
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}
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}
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return false
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}
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func Test(t *testing.T) {
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matrix := [][]int{{1, 3, 5, 7}, {10, 11, 16, 20}, {23, 30, 34, 60}}
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target := 3
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fmt.Println(searchMatrix(matrix, target))
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target = 13
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fmt.Println(searchMatrix(matrix, target))
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}
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@@ -0,0 +1,58 @@
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package top100liked
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import (
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"fmt"
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"testing"
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)
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// https://leetcode.cn/problems/find-first-and-last-position-of-element-in-sorted-array/?envType=study-plan-v2&envId=top-100-liked
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func binarySearch(nums []int, target int) int {
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start := 0
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end := len(nums) - 1
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for start <= end {
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midIdx := start + (end-start)/2
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mid := nums[midIdx]
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if mid == target {
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return midIdx
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} else if mid > target {
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end = midIdx - 1
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} else if mid < target {
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start = midIdx + 1
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}
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}
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return -1
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}
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func searchRange(nums []int, target int) []int {
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res := binarySearch(nums, target)
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if res == -1 {
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return []int{-1, -1}
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}
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l, r := res-1, res+1
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for l >= 0 {
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_l := binarySearch(nums[:l+1], target)
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if _l == -1 {
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break
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} else {
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l = _l - 1
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}
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}
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for r < len(nums) {
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_r := binarySearch(nums[r:], target)
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if _r == -1 {
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break
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} else {
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r = r + _r + 1
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}
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}
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return []int{l + 1, r - 1}
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}
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func Test(t *testing.T) {
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nums := []int{5, 7, 7, 8, 8, 10}
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fmt.Printf("%+v\n", searchRange(nums, 8))
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fmt.Printf("%+v\n", searchRange(nums, 6))
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fmt.Printf("%+v\n", searchRange([]int{}, 0))
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}
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@@ -0,0 +1,43 @@
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package top100liked
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import (
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"fmt"
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"testing"
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)
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// https://leetcode.cn/problems/find-minimum-in-rotated-sorted-array/?envType=study-plan-v2&envId=top-100-liked
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func findMin(nums []int) int {
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if len(nums) == 1 {
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return nums[0]
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}
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if nums[0] < nums[len(nums)-1] {
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return nums[0]
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}
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start := 0
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end := len(nums) - 1
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for start <= end {
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mid := start + (end-start)/2
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if mid >= 1 && nums[mid-1] > nums[mid] && mid < len(nums)-1 && nums[mid] < nums[mid+1] {
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return nums[mid]
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}
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if nums[mid] > nums[end] {
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// 最小值在右侧
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start = mid + 1
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} else {
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// 最小值在左侧
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end = mid - 1
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}
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}
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if nums[start] > nums[end] {
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return nums[end]
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}
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return nums[start]
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}
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func Test(t *testing.T) {
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// fmt.Println(findMin([]int{3, 4, 5, 1, 2}))
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// fmt.Println(findMin([]int{3, 1, 2}))
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fmt.Println(findMin([]int{2, 1}))
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}
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